This is easy !
Take 2 as a common factor, you'll get : 2(2x^2+3x+1) solve it with any of the three methods. Let's take the Factorisation method you have to multiply 2x^2 by 1 (ac), find the factors for 3x
=> 2(2x^2+1x+2x+1)
==>2(2x^2+1x) + 2(2x+1)
[ Here in the first bracket, x is a common factor.]
===>2x(2x+1) + 2(2x+1)
You have 2x+1 on both side so...
==> (2x+2) (2x+1).
