Respuesta :

nobillionaireNobley
s(t) = ∫vdt = ∫sin(πt)dt = (-cos(πt))/π + c
s(-3) = (-cos(-3π))/π + c = 0
(-cos(3π))/π + c = 0
1/π + c = c
c = -1/π

Therefore, s(t) = (-cos(πt))/π - 1/π = (-cos(πt) - 1)/π



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