Wedmbiluli4nura
Wedmbiluli4nura
19-11-2016
Mathematics
contestada
Integral of (3x-2)/(x-1)^2
Respuesta :
syed514
syed514
20-11-2016
(3x−2)/
(x−1
)^2
=
A/(
x−1)
+
B/x
(x−1
)^2
=[
A(x−1)+Bx
(x−1
)] / 2
3x-2=A(x-1)+Bx
3x-2=x(A+B)-A
A+B=3
-A=-2=>A=2
A+B=3=>2+B=3=>B=1
lets check our partial fraction we have
2/(
x−1)
+
x/
(x−1
)^2
= [
2(x−1)+x] /
(x−1
)^2
=(
3x−2) /
(x−1
)^2
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