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syed514
From the middle of the hexagon to one of its edges will be 4.A hexagon can be formed from 6 equilateral trianglesThe area of one equilateral triangle in this case is:A=bh/2A=4(sin60*2)A=8sin(60) A of hexagon = 8 * 6sin(60)=16√3
P = 4*6 = 24
haneghan2003

Answer: 6

Step-by-step explanation:

correct on e d g e n u i t y

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