y'sinx=ylny, is equivalent to dy / dx (sinx=ylny, and dy sinx=ylny dx
it is similar to dy/ylny = dx/sinx
so integral (dy/ylny = integral dx/sinx)
integral dx/sinx)= Ln{abs value ( tan(x /2 + pi /4)}
integral (dy/ylny= ln(lny)
final answer is lny = {abs value ( tan(x /2 + pi /4)}+C, you can find y, or x
