teejaytal teejaytal
  • 21-03-2021
  • Mathematics
contestada

Expand and find the coefficient of xy,x² and y² in the following: (x+6y)²

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Аноним Аноним
  • 21-03-2021

Answer:

xy = 12  [tex]x^{2}[/tex] = 1  [tex]y^{2}[/tex] = 36

Step-by-step explanation:

Coefficient means the value/number before those terms.

First, lets expand [tex](x + 6y)^{2}[/tex]

(x + 6y)(x + 6y) = [tex]x^{2} + 6xy + 6xy + 36y^{2}[/tex] = [tex]x^{2} + 12xy + 36y^{2}[/tex]

The coefficient before [tex]x^{2}[/tex] is 1.

The coefficient before xy is 12.

The coefficient before [tex]y^{2}[/tex] is 36.

I hope this helps!! ^-^

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