Answer:
x=0, y=15
Step-by-step explanation:
x/2+y/5=3
(5x+2y)/10=3
5x+2y=30
2y=30-5x
y=(30-5x)/2....(1)
we know, 5x+2y=30
substituting (1)
5x+2×[tex]\frac{30-5x}{2}[/tex]=30
5x+30-5x=30
5x-5x=1
x=0
y= (30-5x)/2= 30/2=15
let's check the answer,
0/2+15/5=3
15/5=3
3=3
LHS=RHS
