(^3-^2+2)D=0
D^2+D^2+2D=0
2D^2+2D=0
a = 2; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·2·0
Δ = 4
D1=−b−Δ√2aD2=−b+Δ√2a
Δ−−√=4√=2
D1=−b−Δ√2a=−(2)−22∗2=−44=−1
D2=−b+Δ√2a=−(2)+22∗2=04=0
