Answer:
Both answers should be -2 and 14.
Step-by-step explanation:
Using the quadratic formula:
[tex]x^{2}-12x-28=0\\\\x=\frac{-(-12)+-\sqrt{(-12)^2-4(1)(-28)} }{2(1)}\\\\x= \frac{12+-\sqrt{144+112} }{2}\\\\x= \frac{12+-\sqrt{256} }{2}\\\\x= \frac{12+-16 }{2}\\\\x=6+-8[/tex]
Therefore:
[tex]x_{1} =6+8=14\\x_{2}=6-8=-2[/tex]
