Answer:
1 and 6
Step-by-step explanation:
it is just like the roots of a polynomial, since [tex]\sqrt{x-1}[/tex](x-6)^2=0
we can separate the two pieces of the problem
\sqrt{x-1} =0
square both sides to get
x-1=0. x=1
(x-6)^2=0
square root both sides and get
x-6=0
x=6
so the two inflection points of the equation are 6 and 1
Hope that helps :)
