Answer:
[tex] x\approx 18.0[/tex]
Step-by-step explanation:
Here, a = 30, b = 16, C = x
By law of cosines
[tex] {c}^{2} = {a}^{2} + {b}^{2} - 2ab \cos C \\ \\ {x}^{2} = {30}^{2} + {16}^{2} - 2 \times 30 \times 16 \: cos 30 \degree \\ \\ {x}^{2} = 900 + 256 - 960 \times \frac{ \sqrt{3} }{2} \\ \\ {x}^{2} = 1156 - 480 \times \sqrt{3} \\ \\ {x}^{2} = 324.615612 \\ \\ x = \sqrt{324.615612} \\ \\ x = 18.0170922 \\ \\ x \approx \: 18.0[/tex]
