Answer:
m = 29.6 grams
Explanation:
Given that,
Number of moles = 0.540
The molar mass of manganese = 54.93 g/mol
We know that,
Number of moles = given mass/molar mass
[tex]m=n\times M\\\\m=0.540 \times 54.93\\\\m=29.6\ g[/tex]
So, the required mass of the Manganese is equal to 29.6 grams.
