anewton8
anewton8 anewton8
  • 19-03-2021
  • Mathematics
contestada


[tex]8x^2+16x+8 [/tex]
Find the real/complex root of 8x^2+16+8​

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Berra2008
Berra2008 Berra2008
  • 19-03-2021
I’m pretty sure it is -1 but I might be wrong so, correct me if I am
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surjithayer10otahza surjithayer10otahza
  • 19-03-2021

Answer:

real root =-1 (repeated)

Step-by-step explanation:

8x²+16x+8

8(x²+2x+1)

8(x+1)²=0

x=-1,-1

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