Answer:
[tex] x = \dfrac{3}{2} [/tex]
Step-by-step explanation:
x^2-3x+9/4 =0
Multiply both sides by 4 to get rid of the fraction.
4x^2 - 12x + 9 = 0
[tex] x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} [/tex]
[tex] x = \dfrac{-(-12) \pm \sqrt{(-12)^2 - 4(4)(9)}}{2(4)} [/tex]
[tex] x = \dfrac{12 \pm \sqrt{144 - 144}}{8} [/tex]
[tex] x = \dfrac{12}{8} [/tex]
[tex] x = \dfrac{3}{2} [/tex]
