Respuesta :
Answer:
20.41 m
Explanation:
Let's list out the relevant variables in this problem. Take the upwards direction to be positive and the downwards to be negative.
- v₀ = 20 m/s
- v = 0 m/s
- a = -9.8 m/s²
- Δy = ?
We are using the fact that at maximum height, the object's velocity is 0 m/s right before it changes direction to fall vertically back down to Earth.
Find the constant acceleration equation that contains these four variables.
- v² = v₀² + 2aΔy
Substitute the known values into the equation and solve for Δy, the maximum height.
- (0)² = (20)² + 2(-9.8)Δy
- 0 = 400 - 19.6Δy
- -400 = -19.6Δy
- Δy = 20.4081632653
The maximum height of the stone is 20.41 m. Notice that its mass was irrelevant when solving for its maximum height when thrown.