Answer:
870
Step-by-step explanation:
Assuming you mean
30[tex]P_{2}[/tex]
Using the definition
n[tex]P_{r}[/tex] = [tex]\frac{n!}{(n-r)!}[/tex]
where n! = n(n - 1)(n - 2) ..... 3 × 2 × 1
Then
30[tex]P_{2}[/tex] = [tex]\frac{30!}{28!}[/tex] = [tex]\frac{30(29)(28)(27)...}{28(27)(26).....}[/tex]
Cancel the terms 28(27)... on numerator/ denominator, leaving
30[tex]P_{2}[/tex] = 30 × 29 = 870
