205823538 205823538
  • 17-03-2021
  • Mathematics
contestada

[tex]2nx^{2} +15n+7\\[/tex]

Respuesta :

lynnkc2000 lynnkc2000
  • 17-03-2021

Answer:

x = ± √(-15n-7) / √2n    (± (-15n-7)^(1/2) / (2n)^(1/2))

Step-by-step explanation:

Factoring?

2nx² + 15n+7 = 0

2nx² + 0*x + (15n+7) = 0  ... ax²+bx+c=0

Roots: x = (-2b ± √b²-4ac)) / 2a = (0 ± √0-4*2n*(15n+7)) / 4n

x = ± (√8n (-15n-7)) / 4n = ± (2√2n(-15n-7)) / 4n = ± (√2n(-15n-7)) / 2n

or x = ± √(-15n-7) / √2n

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