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A 500 kg crate is pushed horizontally with a force of 1500 N. If the coefficient of friction is 0.25, calculate the acceleration of the crate.

Respuesta :

[tex]ma=F-fmg\\a=\frac{F-fmg}{m}=\frac{1500-0.25*500*10}{500} =\frac{1}{2}[\frac{m}{s^2}][/tex]

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