Answer:
It's irrational
Step-by-step explanation:
the square root of 27 is equal to:
[tex]\sqrt{27} = \sqrt{3\cdot3\cdot3} = 3\sqrt{3}[/tex]
We know that [tex]\sqrt{3}[/tex] is an irrational number (but a real number), so [tex]3\sqrt{3}[/tex] is the same.
In case we need to prove that [tex]\sqrt{3}[/tex] is irrational, please leave a comment.
