9514 1404 393
Answer:
1/2
Step-by-step explanation:
The rules of exponents are helpful.
(a^b)^c = a^(bc)
a^-b = 1/a^b
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[tex]25^{\frac{1}{2}}\times10^{-1}=\dfrac{(5^2)^{\frac{1}{2}}}{10^1}=\dfrac{5^{2\cdot\frac{1}{2}}}{10}\\\\=\dfrac{5^1}{10}=\dfrac{5}{10}=\boxed{\dfrac{1}{2}}[/tex]
