Respuesta :

kdefne39

Answer:

[tex]21.0 { { {1221220 = 223jn}^{n \: \: \: \: \: \: \: \: \: \: \: \: \tan( \beta \beta \beta \beta \beta \beta \pi\pi) } }^{2} }^{2} \times \frac{?}{?} [/tex]

Answer:

31° F and 67° F

Step-by-step explanation:

(a)

When t = 0 then

f(0) = 31 + [tex]\frac{0}{100}[/tex] = 31 + 0 = 31° F

(b)

When t = 10 , then

f(10) = 31 + [tex]\frac{40(10^3)}{10^3+100}[/tex] = 31 + [tex]\frac{40000}{1100}[/tex] = 31 + 36.36... ≈ 67° F

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