Answer:
infinitely many solutions
Step-by-step explanation:
Given the simultaneous equation
4x=10+4y... 1
2x-2y=15 .... 2
_____________
4x-4y = 10 * 1
2x-2y = 15 * 2
__________--
4x-4y = 10
4x-4y = 30
Add both equation
8x - 8y = 10+30
8x-8y = 40
Divide though by 8
x-y = 5
x = 5 + y
Since the result gave 1 equation and 2 unknowns, then we will let x =k
k = 5 + y
y = k -5
k can be any integer
(x,y) = (k, k-5)
This show that the equation has infinitely many solutions
