bodhi44 bodhi44
  • 19-02-2021
  • Chemistry
contestada

How many Atoms are present in 155.8 grams of zirconium?

Respuesta :

sarasihner17
sarasihner17 sarasihner17
  • 19-02-2021

Answer: 2.12×10²³ atoms.

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ atoms. This simply means that 1 mole of zirconium also 6.02×10²³ atoms.

Thus, we can obtain the number of atoms present in 0.3521 mole of zirconium as follow:

1 mole of zirconium also 6.02×10²³ atoms.

Therefore, 0.3521 mole of zirconium will contain = 0.3521 × 6.02×10²³ = 2.12×10²³ atoms.

Therefore, 0.3521 mole of zirconium contains 2.12×10²³ atoms.

Answer Link

Otras preguntas

The formula to convert °F to °C is C = (F – 32).Convert 50°C to °F
¿What is the polite command form of tener?
I need help with table “A”
Spanish 2 help on past tense verbs?
Please help A.S.A.P! I also need a catchy introduction for it! HELP ME PARAPHRASE THIS (PLEASE TRY TO ADD NEW IDEAS)! Everyone should live in California! There
Im learning Polynomials and we are learning the strategy grouping, can anyone please explain how to group polynomials and maybe give an example :) greatly appre
What are the high level questions
If someone could answer these that’d be great
The bicycle salesman tried to _____ his cheap and unsafe _____ to unsuspecting cyclists. pedal / peddles paddle / pedals puddle / pebbles peddle / pedals
How did the federal government encourage settlement of the new west?