Consider we need to find the equation of the circle.
Given:
The Center at (-4,-1), radius = 2.
To find:
The equation of the circle.
Solution:
The standard form of a circle is
[tex](x-h)^2+(y-k)^2=r^2[/tex]
Where, (h,k) is the center of the circle and r is the radius of the circle.
Putting h=-4, k=-1 and r=2, we get
[tex](x-(-4))^2+(y-(-1))^2=(2)^2[/tex]
[tex](x+4)^2+(y+1)^2=4[/tex]
Therefore, the equation of the circle is [tex](x+4)^2+(y+1)^2=4[/tex].
