Answer:
[tex]tanD=\frac{7}{24}[/tex]
[tex]tanF=\frac{24}{7}[/tex]
Step-by-step explanation:
We are given that
ED=24units
EF=7units
FD=25 units
We have to find the tangents of the acute angle in the right triangle
We know that
tangent=[tex]\frac{Perpendicular\;side}{Base}[/tex]
Using the formula
[tex]tanD=\frac{EF}{ED}[/tex]
[tex]tanD=\frac{7}{24}[/tex]
[tex]tanF=\frac{ED}{EF}[/tex]
[tex]tanF=\frac{24}{7}[/tex]
