Answer:
[tex]x = 2\sqrt{5}[/tex]
Step-by-step explanation:
Given
The attached triangle
Required
Find x
Using the sin function
[tex]sin(\theta) = \frac{Opposite}{Adjacent}[/tex]
[tex]sin(30) = \frac{\sqrt{5}}{x}[/tex]
Make x the subject
[tex]x = \frac{\sqrt{5}}{sin(30)}[/tex]
[tex]x = \frac{\sqrt{5}}{1/2}[/tex]
Express as:
[tex]x = \sqrt{5}/1/2}[/tex]
[tex]x = \sqrt{5}*2/1[/tex]
[tex]x = \sqrt{5}*2[/tex]
[tex]x = 2\sqrt{5}[/tex]
