Answer:
[tex]J' = (-2,-4)[/tex]
Step-by-step explanation:
Given
The attached figure
[tex]J = (-3,-6)[/tex]
[tex]D_{o,\frac{2}{3}}(x,y)[/tex]
Required: Determine J'
The given transformation: [tex]D_{o,\frac{2}{3}}(x,y)[/tex] means that the quadrilateral is dilated by a scale factor or 2/3.
So, J' is calculated as:
[tex]J' = \frac{2}{3} * J[/tex]
[tex]J' = \frac{2}{3} * (-3,-6)[/tex]
[tex]J' = (\frac{2}{3} * -3,\frac{2}{3} * -6)[/tex]
[tex]J' = (2*-1,2*-2)[/tex]
[tex]J' = (-2,-4)[/tex]
Hence, J' = (-2,-4)
