Given:
The equation is
[tex](-a-b)x=3a+3b[/tex]
To find:
The value of x.
Solution:
We have,
[tex](-a-b)x=3a+3b[/tex]
It can be written as
[tex]x=\dfrac{3a+3b}{(-a-b)}[/tex]
[tex]x=\dfrac{3(a+b)}{-(a+b)}[/tex]
Cancel out the common factors.
[tex]x=\dfrac{3}{-1}[/tex]
[tex]x=-3[/tex]
Therefore, the value of x is -3.
