Answer:
3[tex]\sqrt{5}[/tex]
Step-by-step explanation:
View the distance as a hypotenuse of a triangle ΔABC (∠C = 90°).
Use Pythagorean theorem:
AB = y1 - y2 = 9 - 6 = 3
AC = x1 - x2 = 4 - (-2) = 6
Now calculate BC which is also the distance needed:
[tex]BC^{2} =AC^{2} +AB^{2}[/tex]
[tex]BC^{2}[/tex] = [tex]6^{2} + 3^{2}[/tex] = 45
BC = [tex]\sqrt{45}[/tex] = [tex]\sqrt{3 * 3 * 5}[/tex] (BC > 0)
BC = 3[tex]\sqrt{5}[/tex]
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