Respuesta :

Answer:

Step-by-step explanation:

AC=[tex]\sqrt{20^{2} -12^{2} }[/tex]

AC=16

BC=16-10

BC=6

BD=[tex]\sqrt{12^{2} +6^{2} }[/tex]

BD=13.42(correct to nearest hundredth)

The perimeter of ΔDBC=13.42+6+12

                                       = 31.42

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