Step-by-step explanation:
1. if to calculate the length of AB; AC and BC, then:
[tex]|AB|=\sqrt{(2-0)^2+(3-0)^2} =\sqrt{13}.[/tex]
[tex]|AC|=\sqrt{(4-0)^2+(0-0)^2} =4.[/tex]
[tex]|BC|=\sqrt{(2-4)^2+(0-3)^2}= \sqrt{13}.[/tex]
2. if to compare the calculated lengths, then:
AB=BC. It means the given triangle is isosceles.
