Answer:
[tex]0.361Ca\\\\ 0.639Cl[/tex]
Explanation:
Hello!
In this case, since the mass ratio here can be computed as:
[tex]\frac{mass\ Ca}{mass\ CaCl_2} \\\\\frac{mass\ Cl}{mass\ CaCl_2}[/tex]
For each element forming the compound we obtain:
[tex]\frac{36.1g}{63.9g+36.1g} = 0.361Ca\\\\\frac{63.9g}{63.9g+36.1g} = 0.639Cl[/tex]
Best regards!
