Respuesta :

ChoiSungHyun

Step-by-step explanation:

In Quadrant II, tanθ is negative.

We have tan²θ + 1 = sec²θ.

=> tanθ = - √(sec²θ - 1)

= -√[(-7/3)² - 1]

= -√(40/9)

= -√40/3

= -2√10/3.

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