Answer and Step-by-step explanation:
Trigonometric Function (These only work for right triangles):
SOH-CAH-TOA
S = Sine = sin
C = Cosine = cos
T = Tangent = tan
O = Opposite (side)
H = Hypotenuse (side)
A = Adjacent (side)
SOH = sin(angle) = [tex]\frac{opposite}{hypotenuse}[/tex]
CAH = cos(angle) = [tex]\frac{adjacent}{hypotenuse}[/tex]
TOA = tan(angle) = [tex]\frac{opposite}{adjacent}[/tex]
1. sinQ (Q is the angle) = [tex]\frac{14}{50} = \frac{7}{25} = 0.28[/tex]
Use Pythagorean Theorem to find side PQ. [tex]14^{2} + PQ^{2}= 50^{2} \\PQ^{2} = 2304\\PQ = 48[/tex]
2. cosQ = [tex]\frac{48}{50} = \frac{24}{25} = 0.96[/tex]
3. tanQ = [tex]\frac{14}{48} = \frac{7}{24} = 0.29[/tex]
