Answer:
24.5 moles of mercury are produced
Explanation:
The descomposition of mercury(II) oxide, occurs as follows:
2HgO → 2Hg + O₂
Where 2 moles of HgO produce 2 moles of Hg
In other words, the ratio of descomposition of HgO/Hg is 2/2 = 1:1
That means, if 24.5 moles of mercury(II) oxide descompose:
24.5 moles of mercury are produced
