Answer:
6n - 14
Step-by-step explanation:
Given;
g(n) = 3n+1 and f(n) = 2n-5
We are to find (gof)(n)
(gof)(n) = g(f(n))
g(f(n)) = g(2n-5)
Replace n with 2n-5 in g(n)
g(2n-5) = 3(2n-5) + 1
g(2n-5) = 6n - 15 + 1
g(2n-5) = 6n - 14
Hence (gof)(n) is 6n - 14
