Answer:
[tex]\frac{dy}{dx}[/tex] = 8(2x + 3)³
Step-by-step explanation:
Differentiate using the chain rule
Given
y = f(g(x)) , then
[tex]\frac{dy}{dx}[/tex] = f'(g(x)) × g'(x)
Here
f(x) = [tex](2x+3)^{4}[/tex] ⇒ f'(x) = 4(2x + 3)³
g(x) = 2x + 3 ⇒ g'(x) = 2
Thus
[tex]\frac{dy}{dx}[/tex] = 4(2x + 3)³ × 2
= 8(2x + 3)³
