Answer:
0.81mole
Explanation:
Given:
Volume of carbon monoxide = 18dm³
Unknown
Number of moles of carbon monoxide = ?
Solution:
To solve this problem;
1 mole of any gas at rtp occupies a volume of 22.4dm³
So;
x mole of carbon monoxide will occupy a volume of 18dm³ at rtp
22.4x = 18
x = [tex]\frac{18}{22.4}[/tex] = 0.81mole
