gudetamatama101
gudetamatama101 gudetamatama101
  • 19-01-2021
  • Mathematics
contestada

Find an equation for the perpendicular bisector of the line segment whose endpoints are (-4,-5)and (8,-9)

Respuesta :

clarch19
clarch19 clarch19
  • 19-01-2021

Answer:

y = 3x - 13

Step-by-step explanation:

slope of line segment is -1/3 so a segment perpendicular to this would need a slope of 3

the midpoint for the segment is (2, -7); midpoint formula is [([tex]x_{1}[/tex]+[tex]x_{2}[/tex]/2), ([tex]y_{1}[/tex]+[tex]y_{2}[/tex]/2)]

using slope of 3 and point (2, -7) we can plug into y = mx + b

-7 = 3(2) + b

-7 = 6 + b

b = -13

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