Answer:
5
Step-by-step explanation:
[tex]\triangle ACB \cong \triangle DCE... (given) \\\\
\implies m\angle A = m\angle D... (cact) \\\\
\therefore 50\degree = (10x) \degree \\\\
\therefore 50 = 10x\\\\
\therefore \frac{50\degree}{10}= x \\\\
\therefore 5 = x \\\\
x = 5[/tex]
