Answer:
x = 30° and 330°
Step-by-step explanation:
Assuming the intervals is {0 , 2π} or {0° , 360°}
[tex]tan\ x=\frac{-\sqrt{3} }{3} \\\\x=tan^{-1} (\frac{-\sqrt{3} }{3})\\\\x = -30[/tex]
So it means it lies in the 2nd and 4th quadrant because tangent is negative in the 2nd and 4th quadrant
so the two solutions are
x = 30° and 330° or
[tex]x=\frac{\pi }{6}\ radians\ \ , \ \ \frac{11\pi }{6}\ radians[/tex]
