cavasosjoaquin06
cavasosjoaquin06 cavasosjoaquin06
  • 18-12-2020
  • Mathematics
contestada

Solve the system by substitution.
4y =
5x -10y =-50

Respuesta :

Dead3ill
Dead3ill Dead3ill
  • 18-12-2020

Answer:

[tex]x = -20 ; y =-5[/tex]

Step-by-step explanation:

Eqn. 1 ----> 4y = x

Eqn. 2 ----> 5x-10y = -50

(Simplifying eqn.2 further)

[tex]=>5(x-2y)=-50[/tex]

[tex]=>x-2y=\frac{-50}{5} =-10[/tex]

(Substituting the value of x from eqn. 1)

[tex]=>4y-2y=-10[/tex]

[tex]=>2y=-10[/tex]

[tex]=>y =\frac{-10}{2} =-5[/tex]

Now, substituting the value of y in eqn. 1 ,

[tex]x = 4*(-5)=-20[/tex]

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