Answer:
B. 56°
Step-by-step explanation:
[tex] 20 \degree = \frac{1}{2} (96 \degree - \widehat{LN}) \\ \\ 2 \times 20 \degree = (96 \degree - \widehat{LN}) \\ \\ 40 \degree = (96 \degree - \widehat{LN }) \\ \\ \widehat{ln} = 96 \degree - 40 \degree \\ \\ \huge \red{ \widehat{LN} = 56 \degree}[/tex]
