An object is traveling at a constant speed of 12.0 m/s when it slows to a stop. If it takes 10.0 m for the object to stop, what is the magnitude of its acceleration?

Question

20-10-2016
Physics

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An object is traveling at a constant speed of 12.0 m/s when it slows to a stop. If it takes 10.0 m for the object to stop, what is the magnitude of its acceleration?

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AL2006 AL2006 · Answer 1 · 2016-10-20T01:15:48+02:00

Magnitude of acceleration =

   (change in speed) divided by (time for the change).

Change in speed =

   (speed at the end of the time) - (speed at the beginning of the time)

   = (zero) minus (12 m/s) = -12 m/s

Time to stop:
I'm not sure whether you meant to write 10 seconds or 10 minutes.

If it's 10 seconds, then

   Acceleration = (-12 m/s) / (10 seconds) = -1.2 m/s²

If it's 10 minutes (600 seconds), then

   Acceleration = (-12 m/s) / (600 seconds)

   = - 0.02 m/s² .