the perimeter of the field is 442
width=w
the length of the field is 9 yards less than quadruple W
L=4x - 9
the perimeter is P=2L+2W
you can plug in the values
P= 2(4w-9) + 2W
plug in 442 for P
442= 2(4w- 9) + 2W
442= 8w - 36 + 2W
478 =8w + 2W
478= 10W
47.8 is your answer!!!
