Respuesta :

VectorFundament120

[tex]y=x^2-4x+6\\y'=2x-4[/tex]

To find the slope/gradient of the curve at the specific point, we use the derivative.

Then substitute x = 3 in y' = 2x-4

[tex]y'=2(3)-4\\y'=6-4\\y'=2[/tex]

Therefore, the slope/gradient of y = x²-4x+6 at (3,3) is 2.

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