edw2197093 edw2197093
  • 16-12-2020
  • Mathematics
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Write a equation of a line perpendicular to the line below in point-slope from that passes through the point (-2,6)

Write a equation of a line perpendicular to the line below in pointslope from that passes through the point 26 class=

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devdevjc devdevjc
  • 16-12-2020

Answer:

Option 1: [tex]y-6=-4(x+2)[/tex]

Step-by-step explanation:

Find the slope of the perpendicular line by finding the negative reciprocal of the original slope. (Negative reciprocal = flip upside down and add a negative). So we get -4 for the perpendicular slope.

Next, we know the point (-2,6) is on the line, so we can get x=-2 and y=6.

Plug this into point-slope form: [tex]y_{1}-y_{2}=m(x_{1}=x_{2})[/tex]

[tex]y_{1} - (6)=-4(x_{1}-(-2))[/tex]

[tex]y-6=-4(x+2)[/tex]

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