Answer:
Explanation:
no of moles of C2H6=10/30=0.33
complete combustion of 2 moles of ethane produce 4 moles of CO2 therefore 0.33 moles of C2H6 produced 0.66 moles of CO2
now moles =given mass/molar mass
mass= moles*molar mass
mass of CO2=0.67*44=29.48 g
