Answer:
A
Step-by-step explanation:
Given
f(x) = x + [tex]\frac{\sqrt{x+1} }{x-1}[/tex]
To evaluate f(3), substitute x = 3 into f(x) , that is
f(3) = 3 + [tex]\frac{\sqrt{3+1} }{3-1}[/tex]
= 3 + [tex]\frac{\sqrt{4} }{2}[/tex]
= 3 + [tex]\frac{2}{2}[/tex]
= 3 + 1
= 4 → A
