Answer:
Mass of water = 36 g
Explanation:
Given data:
Amount of energy released = 1367 J = 1367/4.184 = 327 cal
Initial temperature = 45.2 °C
Final temperature = 36.2 °C
Amount of water = ?
Solution:
Specific heat capacity of water is 1 cal/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 36.2 °C - 45.2 °C
ΔT = -9°C
-327 cal = m×1 cal/g.°C × -9°C
m = -327 cal/-9cal/g
m = 36 g
